Question 30954: Please help me solve:
{16x^3y/-4xy^3}*{2xy/-x^-1}
My progress: {16x^3y/-4xy^3}*{2xy/-x^-1} = {-4x^2/y^-2}* {{2xy * -x}/1}
= {-8x^3y *-x}/y^-2
= ??? Answer by kietra(57) (Show Source):
You can put this solution on YOUR website! You have a great start to your solution. You've done most of the steps correctly!
Before I finish this problem, let's review what 1/x^-1 is. When you have anything to the -1 power. that means the inverse of what you have. So the inverse of 1/x^-1 is x/1. If you had x^-1, the inverse would be 1/x. If you have the negative sign in the exponent, you won't have to add a negative sign to the number. BAsically, all you have to do is move the number to the top or bottom to get rid of the negative sign.
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