Question 309438: I got this equation so far for this problem but I am at a loss on how to solve it. Here is the word problem:
Your business has the copy machine break down. After having it repaired, you receive a bill for a total of $140 for 8 hours of work. The bill is itemized to show that the full-time mechanic was paid $50 and the part-time mechanic was paid $90. There was more than one thing wrong and you opted to have the easy thing fixed by the parttime mechanic who earns $10 less per hour than the full-time mechanic. How many hours did each worker spend fixing the copier?
My equation began with fulltime xt=50 and parttime (x-10)(8t)=90.
How do I solve this equation?
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! a+b=8
a=8-b
x*a+y*b=140
a*x=90
b*y=50
y=50/b
x=y-10
x*a+y*b=140
(50/b-10)(8-b)+50=140
b=2
b=20
a+20=8
a=-12 discard
b=20 discard
a+2=8
a=6
a = 6, b = 2, x = 15, y = 25
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