SOLUTION: Please help me solve the following problem. Welder A works 3 times faster than welder B. Together they can do a job in 3 hours. How fast can the faster welder do the job by hims

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Please help me solve the following problem. Welder A works 3 times faster than welder B. Together they can do a job in 3 hours. How fast can the faster welder do the job by hims      Log On


   



Question 30924: Please help me solve the following problem. Welder A works 3 times faster than welder B. Together they can do a job in 3 hours. How fast can the faster welder do the job by himself? Thank you very much for helping me to solve this problem.
Found 2 solutions by acerX, mbarugel:
Answer by acerX(62) About Me  (Show Source):
You can put this solution on YOUR website!
Welder A -> 3x
Welder B -> x
Total Time -> 3 hours
The equation would be:
3x%2Bx=3
4x=3
x=3%2F4
Welder A -> 3x
3%2A%283%2F4%29
9%2F4+hours or 2.25hours

Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
The previous answer you got for this question is actually incorrect.
This kind of problems can be solved in the following way. Let's call X to the rate at which welder A does the job per hour. For example, if he could complete the job in 10 hours, then this rate would be 1/10. He completes one tenths of the job per hour. Let's call Y to the same rate for Welder B.
We know that A's rate is 3 times higher than B's:
X+=+3Y
We also know thta if they work together, they complete the work in 3 hours. The rate at which they work together is X + Y. If they complete it in 3 hours, then the rate should be 1/3: they complete one third of the job per hour. So we have:
X%2BY=1%2F3
Replacing the 1st equation in the last one:
3Y+%2B+Y+=+1%2F3
4Y+=+1%2F3
Y=1%2F12
So Welder B by himself can complete the job in 12 hours. Since A is 3 times faster, he can complete the job by himself in 4 hours.


I hope this helps!
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