SOLUTION: Divide: (b^3 - 2b^2 - 33b - 7) / (b - 7)

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Question 309235: Divide: (b^3 - 2b^2 - 33b - 7) / (b - 7)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Divide: (b^3 - 2b^2 - 33b - 7) / (b - 7)
Using synthetic division:
7)....1....-2....-33....-7
.......1....5.....2...|..7

Quotient: b^2 + 5b + 2
Remainder: 7
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Cheers,
Stan H.
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