SOLUTION: I need help solving this:
Log4X-Log4(X-4)=1
the first two 4's are the bases.
I tried distributing the second log by writing it like this:
log4X-log4X-log4(4)=1
and then I
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-> SOLUTION: I need help solving this:
Log4X-Log4(X-4)=1
the first two 4's are the bases.
I tried distributing the second log by writing it like this:
log4X-log4X-log4(4)=1
and then I
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Question 309224: I need help solving this:
Log4X-Log4(X-4)=1
the first two 4's are the bases.
I tried distributing the second log by writing it like this:
log4X-log4X-log4(4)=1
and then I canceled out the first two and was left with -log4(4)=1 and I have no idea what I'm doing past that or even if that's right. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Log4X-Log4(X-4)=1
the first two 4's are the bases.
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x/(x-4) = 4
x = 4(x-4)
x = 4x-16
3x = 16
x = 16/3
