SOLUTION: Did I do this right? (4/3)^-2=(3/4)^-2=(3*3)/(4*4)=9/16=-16/9 If I didn't can you explain what I did wrong and give me the right answer please?
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Exponential-and-logarithmic-functions
-> SOLUTION: Did I do this right? (4/3)^-2=(3/4)^-2=(3*3)/(4*4)=9/16=-16/9 If I didn't can you explain what I did wrong and give me the right answer please?
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Question 309196: Did I do this right? (4/3)^-2=(3/4)^-2=(3*3)/(4*4)=9/16=-16/9 If I didn't can you explain what I did wrong and give me the right answer please? Found 2 solutions by ichudov, Alan3354:Answer by ichudov(507) (Show Source):
You can put this solution on YOUR website! you did it wrong when you said that
That just makes no sense.
The right thing to say is
Since you seem to have a handle on these problems, I would suggest finishing by yourself.
You can put this solution on YOUR website! (4/3)^-2=(3/4)^-2=(3*3)/(4*4)=9/16=-16/9
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You inverted too many times, then you made it negative.
