SOLUTION: solve each equation by taking the square root of each side. round to the nearest tenth if necessary.
c^2-12x+36=4
b^2+16b+64=9
y^2+2y+1=3
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-> SOLUTION: solve each equation by taking the square root of each side. round to the nearest tenth if necessary.
c^2-12x+36=4
b^2+16b+64=9
y^2+2y+1=3
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Question 309169: solve each equation by taking the square root of each side. round to the nearest tenth if necessary.
c^2-12x+36=4
b^2+16b+64=9
y^2+2y+1=3 Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! c^2-12x+36=4
(c-6)^2=2^2
c-6=2
c=2+6
c=8 ans.
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b^2+16b+64=9
(b+8)^2=3^2
b+8=3
b=3-8
b=-5 ans.
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y^2+2y+1=3
(y+1)^2=sqrt3
y+1=1.732
y=1.732-1
y=.7 ans.
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