SOLUTION: Solve by graphing. x^2+4x+3=0, x^2-6x+9=0, and x^2-4x+5=0

Algebra ->  Graphs -> SOLUTION: Solve by graphing. x^2+4x+3=0, x^2-6x+9=0, and x^2-4x+5=0      Log On


   

Question 309168: Solve by graphing. x^2+4x+3=0, x^2-6x+9=0, and x^2-4x+5=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B4x%2B3=0

Crosses the x-axis at x=-1 and x=-3, two unique real roots.
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+x%5E2-6x%2B9=0

Crosses the x-axis at x=-3, a double root.
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+x%5E2-4x%2B5=0+

Never crosses the x-axis, no real roots.