SOLUTION: what is the equation of the axis of symmetry, the coordinates of the vertex of the graph of each function for y=x^2-2x-5, y=-x^2+4x-1, y=2x^2+4x-2

Algebra ->  Graphs -> SOLUTION: what is the equation of the axis of symmetry, the coordinates of the vertex of the graph of each function for y=x^2-2x-5, y=-x^2+4x-1, y=2x^2+4x-2      Log On


   

Question 309165: what is the equation of the axis of symmetry, the coordinates of the vertex of the graph of each function for y=x^2-2x-5, y=-x^2+4x-1, y=2x^2+4x-2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to vertex form y=a%28x-h%29%5E2%2Bk by completing the square.
Then the corrdinates of the vertex are (h,k) and the axis of symmetry is x=h.
y=x%5E2-2x-5
y=%28x%5E2-2x%2B1%29-5-1
y=%28x-1%29%5E2-6
Vertex : (1,-6)
Axis of Symmetry:x=1

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y=-x%5E2%2B4x-1
y=-%28x%5E2-4x%2B4%29-1%2B4
y=-%28x-2%29%5E2%2B3
Vertex : (2,3)
Axis of Symmetry:x=2

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y=+2x%5E2%2B4x-2+
y=2%28x%5E2%2B2x%2B1%29-2-2
y=2%28x%2B1%29%5E2-4
Vertex : (-1,-4)
Axis of Symmetry:x=-1