Question 309138: what is the equation of a line that goes through points (-1,1)and(3,-11)?
Answer by texttutoring(324)   (Show Source):
You can put this solution on YOUR website! Use the slope equation to find the slope.
slope = m = y2-y1 / x2-x1
m=(-11-1)/(3--1)
m=-12/4
m=-3
Now use y=mx+b, the equation of a line, to solve for b. You can choose either (-1,1) or (3,-11) as your x and y points.
I'll choose (-1,1).
y=mx+b
1 = (-3)(-1) + b
1 = 3 + b
-2 = b
The equation of your line is y = -3x - 2
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