SOLUTION: Solve 2log4-log3+2logx-4=0. a. 12.3308 b. 43.3013 c. 86.6025 d. 1875

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve 2log4-log3+2logx-4=0. a. 12.3308 b. 43.3013 c. 86.6025 d. 1875      Log On


   



Question 309126: Solve 2log4-log3+2logx-4=0.
a. 12.3308
b. 43.3013
c. 86.6025
d. 1875

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve 2log4-log3+2log(x-4)=0.
----
log(16)-log(3) + log(x)^2 = 4
log(16/3)(x)^2) = 4
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(16/3)x^2 = 10^4
x^2 = (3/16)10^4
---
x = (100/4)sqrt(3)
x = 25*sqrt(3)
x = 43.3013
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Cheers,
Stan H.
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a. 12.3308
b. 43.3013
c. 86.6025
d. 1875