Question 308762: when x^7+kx-2 is divided by x-1, the remainder is 7. what is the value of k? Found 2 solutions by user_dude2008, Syzy144:Answer by user_dude2008(1862) (Show Source):
You can put this solution on YOUR website! use remainder theorem x-1 gives remainder 7 ----> (1)^7+k(1)-2=7 ---> 1+k-2=7 ---> k-1=7 ----> k=8
You can put this solution on YOUR website! f(x) =x^7+kx-2
*Plug the remainder in the 'f(X)'.
7=x^7+kx-2
*x-1=0 therefore, x=1. Substitue x for 1 in the equation.
7=1^7+1k-2
7= 1 + 1k - 2
7-1+2=k
8=k
k = 8
(
