SOLUTION: Hello, I am having a very difficult time figuring this statistics problem. I appreciate any help.
A study of 47 golfers show that their average score on a particular course was
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Hello, I am having a very difficult time figuring this statistics problem. I appreciate any help.
A study of 47 golfers show that their average score on a particular course was
Log On
Question 308673: Hello, I am having a very difficult time figuring this statistics problem. I appreciate any help.
A study of 47 golfers show that their average score on a particular course was 97. The standard deviation of the sample is 7. Find the 99% confidence interval of the mean score for all golfers. Found 2 solutions by rapaljer, Fombitz:Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! The 99% confidence level means that you include 3 standard deviations from the mean. In this case, the standard deviation is 7, and 3*7=21. Now, from the mean of 97, both ADD and SUBTRACT 21:
97-21=76
97+21=118
The interval is from 76 to 118. In other words, 99% of the golfers scored between 76 and 118 on this golf course.
You can put this solution on YOUR website! You know the mean, the standard deviation, the confidence interval, and the number of golfers.
Plug the data into the formula.
()
At 99%,
