SOLUTION: Which of the following statements must be true when a^2 < b^2 and a and b are not 0? I. a^2/a < b^2/a II. 1/a^2 > 1/b^2 III. (a + b) (a - b) < 0

Algebra ->  Inequalities -> SOLUTION: Which of the following statements must be true when a^2 < b^2 and a and b are not 0? I. a^2/a < b^2/a II. 1/a^2 > 1/b^2 III. (a + b) (a - b) < 0       Log On


   



Question 308661: Which of the following statements must be true when a^2 < b^2 and a and b are not 0?
I. a^2/a < b^2/a
II. 1/a^2 > 1/b^2
III. (a + b) (a - b) < 0

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I. Clearly this is false. If a%3C0, then the inequality sign should flip, but it does not. If the sign did flip, then it would only be true for negative values of 'a', but what if 'a' was positive? Since we have this uncertainty, statement I is false.


II. If a%3C%3E0 and b%3C%3E0, then a%5E2 and b%5E2 are both positive numbers. Recall that if x%3Cy and 'x' and 'y' are both positive, then 1%2Fx%3E1%2Fy which shows us that statement II is true.


III.


a%5E2+%3C+b%5E2 Start with the given inequality.


a%5E2+-+b%5E2+%3C+0 Subtract b%5E2 from both sides.


%28a%2Bb%29%28a-b%29+%3C+0 Factor the left side using the difference of squares.


So statement III is true.