SOLUTION: The sum of three consecutive integers is k. What is the greatest of these integers in terms of k? a) (1/3k)-1 b) (1/3k)+ 1 c) k - 3 d) k + 2 e) 3k + 3

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The sum of three consecutive integers is k. What is the greatest of these integers in terms of k? a) (1/3k)-1 b) (1/3k)+ 1 c) k - 3 d) k + 2 e) 3k + 3      Log On


   



Question 308623: The sum of three consecutive integers is k. What is the greatest of these integers in terms of k?
a) (1/3k)-1 b) (1/3k)+ 1 c) k - 3 d) k + 2 e) 3k + 3

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The three consecutive integers are N, N+1, and N+2.
+N%2B%28N%2B1%29%2B%28N%2B2%29=k
Solve for N.
+3N%2B3=k
+3N=k-3
+N=%28k-3%29%2F3
Now solve for N+2 which is the greatest of the three integers.
+N%2B2=%28k-3%29%2F3%2B6%2F3
+N%2B2=%28k-3%2B6%29%2F3
+N%2B2=%28k%2B3%29%2F3
+N%2B2=k%2F3%2B1
.
.
.
b) is the correct answer.