SOLUTION: Lisa has nine rings in her jewelry box. Five are gold and four are silver. If she randomly selects 3 rings to wear to a party, find each probality:
P(2 silver or 2 gold)
P(at
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-> SOLUTION: Lisa has nine rings in her jewelry box. Five are gold and four are silver. If she randomly selects 3 rings to wear to a party, find each probality:
P(2 silver or 2 gold)
P(at
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Question 308569: Lisa has nine rings in her jewelry box. Five are gold and four are silver. If she randomly selects 3 rings to wear to a party, find each probality:
P(2 silver or 2 gold)
P(at least 2 gold) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Lisa has nine rings in her jewelry box. Five are gold and four are silver. If she randomly selects 3 rings to wear to a party, find each probability:
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P(2 silver or 2 gold) = P(2 silver) + P(2 gold) = 5C2/9C2 + 4C2/9C2
= [10+6]/36 = 4/9
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P(at least 2 gold) = P(2 gold) + P(3 gold) = 5C2/9C2 + 5C3/9C2
= [10+10]/36 = 5/9
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Cheers,
Stan H.
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