SOLUTION: Please help me solve the following equation....I'm beginning to think the solution in the answer book is wrong: x/x-1 minus 1/x = 3/2.....solve for x. Thanks in advance

Algebra ->  Expressions-with-variables -> SOLUTION: Please help me solve the following equation....I'm beginning to think the solution in the answer book is wrong: x/x-1 minus 1/x = 3/2.....solve for x. Thanks in advance       Log On


   

Question 308429: Please help me solve the following equation....I'm beginning to think the solution in the answer book is wrong:
x/x-1 minus 1/x = 3/2.....solve for x.
Thanks in advance
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%2F%28x-1%29-1%2Fx=3%2F2
Multiply both sides by 2x%28x-1%29
2x%5E2-2%28x-1%29=3x%28x-1%29
2x%5E2-2x%2B2=3x%5E2-3x%29
x%5E2-x-2=0%29
Factor
%28x-2%29%28x%2B1%29=0
Two solutions:
x-2=0
x=2
.
.
.
x%2B1=0
x=-1
.
.
.
Verify the solutions by plugging them back into the original equation.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve the following equation....I'm beginning to think the solution in the answer book is wrong:
x/(x-1) minus 1/x = 3/2.....solve for x.
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Multiply both sides by 2x(x-1) to get:
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2x^2 - 2(x-1) = 3x(x-1)
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2x^2 -2x + 2 = 3x^2 - 3x
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x^2 - x - 2 = 0
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(x-2)(x+1) = 0
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Potential answers:
x = -1 or x = 2
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Checking you will find that both are answers.
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Cheers,
Stan H.