SOLUTION: Please help me with this fraction- [ (x^2 + 3x + 9) / (x^2 – 9) ][ (x + 3) / (x^3 - 27) ]
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Question 308280
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Please help me with this fraction-
[ (x^2 + 3x + 9) / (x^2 – 9) ][ (x + 3) / (x^3 - 27) ]
Answer by
mananth(16946)
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[ (x^2 + 3x + 9) / (x^2 – 9) ][ (x + 3) / (x^3 - 27) ]
(x^2 + 3x + 9)/(x+3)(x-3) * (x+3)(x-a)/(x^2+3x+9)
x-3 / x-a