SOLUTION: Here is another complex fraction I need to figure out. (9 / m^2 - m - 2) - (6 / m^2 - 1)

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Question 308250: Here is another complex fraction I need to figure out.
(9 / m^2 - m - 2) - (6 / m^2 - 1)
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(9 / m^2 - m - 2) - (6 / m^2 - 1)
9 / (m-2)(m+1) - 6 /(m+1)(m-1)
subtract the fractions
LCM = (m+1)(m-1)(m-2)
9(m-1) - 6(m-2) / (m+1)(m-1)(m-2)
9m-9-6m+12 / (m+1)(m-1)(m-2)
3m-3 /(m+1)(m-1)(m-2)
3(m-1)/(m+1)(m-1)(m-2)
3/(m+1)(m-2)