Question 308011: solve the equation e^(2x)=20 for x ....
a. x=10/e
b. x=1n20/2
c. x=1n10
d. x=20-e/2
tthanks!
Found 2 solutions by rapaljer, texttutoring:
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! e^(2x) = 20
ln(e^(2x))= ln 20
2x= ln 20
 . The correct answer is B).
You may want to see my website for help with LOGARITHMS! To find my website, just click on my tutor name "Rapaljer" anywhere in algebra.com. For written explanations, look for "Basic, Intermediate, and College Algebra: One Step at a Time", choose "College Algebra" and look for "Chapter 4 Logarithms." See also the "MATH IN LIVING COLOR" pages that go with this explanation, where the exercises are solved IN COLOR!
For VIDEO explanations, on my Homepage look for "Rapalje Videos in Living Color". Choose "College Algebra" and select the topics of "Logarithms." These videos are from my own classroom a few years ago before I retired. I hope you find these helpful.
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Answer by texttutoring(324)  (Show Source):
You can put this solution on YOUR website! You have to 'take the natural log' of both sides.
The natural log, LN, is the inverse function of the exponential e^
ln(e^2x) = ln(20)
2x=ln20
x=ln20/2
The answer is b.
|
|
|
