SOLUTION: solve the equation e^(2x)=20 for x .... a. x=10/e b. x=1n20/2 c. x=1n10 d. x=20-e/2 tthanks!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: solve the equation e^(2x)=20 for x .... a. x=10/e b. x=1n20/2 c. x=1n10 d. x=20-e/2 tthanks!      Log On


   



Question 308007: solve the equation e^(2x)=20 for x ....
a. x=10/e
b. x=1n20/2
c. x=1n10
d. x=20-e/2
tthanks!

Found 2 solutions by Fombitz, rapaljer:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
e%5E%282x%29=20+
ln%28e%5E%282x%29%29=ln%2820%29
2x=ln%2820%29
x=%281%2F2%29ln%2820%29
I'm not sure which answer it is but this is the correct answer.

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Start by taking the ln of each side of the equation to "undo" the "e^":
e%5E%282x%29=20
ln%28e%5E%282x%29%29=+ln+20
2x=+ln+20

Divide by 2:
x=+ln20%2F2

You may want to see my website for help with LOGARITHMS! To find my website, just click on my tutor name "Rapaljer" anywhere in algebra.com. For written explanations, look for "Basic, Intermediate, and College Algebra: One Step at a Time", choose "College Algebra" and look for "Chapter 4 Logarithms." See also the "MATH IN LIVING COLOR" pages that go with this explanation, where the exercises are solved IN COLOR!

For VIDEO explanations, on my Homepage look for "Rapalje Videos in Living Color". Choose "College Algebra" and select the topics of "Logarithms." These videos are from my own classroom a few years ago before I retired. I hope you find these helpful.

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus