SOLUTION: Three consecutive integers are such that the square of the first is 29 less then the product of the other two
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Question 307893
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Three consecutive integers are such that the square of the first is 29 less then the product of the other two
Answer by
nyc_function(2741)
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Here is your equation and you can finish:
x^2 = (x + 1)(x + 2) - 29
