SOLUTION: Given the function f:x (maps to) 6x-2/x, x>0. Find the value of: a.)f^-1(-1) b.)f^-1(-4)

Algebra ->  Functions -> SOLUTION: Given the function f:x (maps to) 6x-2/x, x>0. Find the value of: a.)f^-1(-1) b.)f^-1(-4)      Log On


   

Question 30766: Given the function f:x (maps to) 6x-2/x, x>0.
Find the value of:
a.)f^-1(-1)
b.)f^-1(-4)
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
i have no idea what you mean: Either %286x-2%29%2Fx or 6x-%282%2Fx%29? Please learn to use brackets.

I shall guess at %286x-2%29%2Fx

So, +y+=+%286x-2%29%2Fx+
+xy+=+6x-2+
+xy+-+6x+=+-2+
+x%28y+-+6%29+=+-2+
+x+=+-2%2F%28y+-+6%29+

so, +f%5E%28-1%29%28x%29+=+-2%2F%28x-6%29+

So, +f%5E%28-1%29%28-1%29+=+-2%2F%28-7%29+
+f%5E%28-1%29%28-1%29+=+2%2F7+

and +f%5E%28-1%29%28-4%29+=+-2%2F%28-4-6%29+
+f%5E%28-1%29%28-4%29+=+-2%2F%28-10%29+
+f%5E%28-1%29%28-4%29+=+2%2F10+
+f%5E%28-1%29%28-4%29+=+1%2F5+

jon.