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Question 307640: The sum of two numbers is six less than twice the first number. When the second number is subtracted from the first, the difference is ten less than four times the second number. What is the second number?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Let x = a number
Let y = a second number
:
Write an equation for each statement, then simplify the equation:
:
"The sum of two numbers is six less than twice the first number."
x + y = 2x - 6
y = 2x - x - 6
y = (x - 6)
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" When the second number is subtracted from the first, the difference is ten less than four times the second number."
x - y = 4y - 10
x = 4y + y - 10
x = 5y - 10
replace y with (x-6), find x
x = 5(x-6) - 10
x = 5x - 30 - 10
x - 5x = -40
-4x = -40
x = +10
find y
y = 10 - 6
y = 4 is the 2nd number
:
Check solution in the 1st statement:
"The sum of two numbers is six less than twice the first number."
10 + 4 = 2(10) - 6
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