SOLUTION: What are the correct steps of solving this problem sqrt( 4x-1 )= sqrt( 3x+5 ) I just want to make sure but i assume to square both sides to cancel the square root making them

Algebra ->  Square-cubic-other-roots -> SOLUTION: What are the correct steps of solving this problem sqrt( 4x-1 )= sqrt( 3x+5 ) I just want to make sure but i assume to square both sides to cancel the square root making them      Log On


   

Question 307618: What are the correct steps of solving this problem
sqrt( 4x-1 )= sqrt( 3x+5 )
I just want to make sure but i assume to square both sides to cancel the square root making them 4x-1 = 3x+5 and then subtracting the 3x making it 1x-1= 5 then add the one making it 1x = 6 then divide by one making it x = 6
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
hat are the correct steps of solving this problem
sqrt( 4x-1 )= sqrt( 3x+5 )
I just want to make sure but i assume to square both sides to cancel the square root making them 4x-1 = 3x+5 and then subtracting the 3x making it 1x-1= 5 then add the one making it 1x = 6 then divide by one making it x = 6
:
You don't need to bother to divide by 1, but that is correct, you can confirm this on your calc:
Enter sqrt%284%286%29-1%29 = 4.7958...
Enter sqrt%283%286%29%2B5%29 = 4.7958...