SOLUTION: trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a

Algebra ->  Functions -> SOLUTION: trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a      Log On


   



Question 307359: trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a station at 6:10 A.M. If train B passes the same station at 6:25 A.M., at what time will train B catch up to train A?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a station at 6:10 A.M. If train B passes the same station at 6:25 A.M., at what time will train B catch up to train A?
:
from the given information, we know that train B is 15 min (1/4 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: 1%2F4 * 100 = 25 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 25 mi
100t = 80t + 25
100t - 80t = 25
20t = 25
t = 25%2F20
t = 1.25 or 1 hr 15 min
:
6:10 + 1:15 = 7:25 AM, B catches A