SOLUTION: i need your help on logarithm, please. how do you find out the solution of the problem if it has a coefficient and an exponent? ex: 5log6^(x+1)=5 are you supposed to divide by 5 b

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: i need your help on logarithm, please. how do you find out the solution of the problem if it has a coefficient and an exponent? ex: 5log6^(x+1)=5 are you supposed to divide by 5 b      Log On


   

Question 306997: i need your help on logarithm, please. how do you find out the solution of the problem if it has a coefficient and an exponent? ex: 5log6^(x+1)=5
are you supposed to divide by 5 because of the coefficient? how do i figure this problem out?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
5log%286%5E%28x%2B1%29%29=+5
Write it using the log equiv of exponents
5%28x%2B1%29log%286%29=+5
divide both sides by the log(6)
5(x+1) = 5%2Flog%286%29
using a calc
5(x+1) = 6.425486
:
5x + 5 = 6.425486
:
5x = 6.425486 - 5
:
5x = 1.425486
x = 1.425486%2F5
x = .2851
:
:
Check on a calc: enter 5*log(6^(.2851+1)) = . 5.000