SOLUTION: A grocer at a specialty store is mixing coffee worth $6 per pound with coffee worth $8 per pound. He wants to obtain 144 pounds of coffee worth $7.50 per pound.How much of each cof

Algebra ->  Equations -> SOLUTION: A grocer at a specialty store is mixing coffee worth $6 per pound with coffee worth $8 per pound. He wants to obtain 144 pounds of coffee worth $7.50 per pound.How much of each cof      Log On


   

Question 306913: A grocer at a specialty store is mixing coffee worth $6 per pound with coffee worth $8 per pound. He wants to obtain 144 pounds of coffee worth $7.50 per pound.How much of each coffee should he use?
Amount of coffee X=108
Amount of coffee Y=36
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
8x+6(144-x)=7.50*144
8x+864-6x=1,080
2x=1,080-864
2x=215
x=216/2
x=108 pounds of $8 coffee is uded.
144-108=36 pounds of $6 coffee is used.
Proof:
8*108+6*36=7.50*144
864+216=1,080
1,080=1,080