SOLUTION: you have 4 blue cards, 1 red card, and 3 green cards. You draw a card, do not replace it, and draw a second card. Find each probability. P(green, then red) P(blue, then gre

Algebra ->  Probability-and-statistics -> SOLUTION: you have 4 blue cards, 1 red card, and 3 green cards. You draw a card, do not replace it, and draw a second card. Find each probability. P(green, then red) P(blue, then gre      Log On


   

Question 306777: you have 4 blue cards, 1 red card, and 3 green cards. You draw a card, do not replace it, and draw a second card. Find each probability.
P(green, then red)
P(blue, then green)
P(red, then blue)



Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4 Blue,B
1 Red,R
3 Green,G
8 Total
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P(G)=3%2F8
P(R)=1%2F7
P(G then R)=%283%2F8%29%281%2F7%29=3%2F56
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P(B)=4%2F8=1%2F2
P(G)=3%2F7
P(B then G)=%281%2F2%29%283%2F7%29=3%2F14
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.
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P(R)=1%2F8
P(B)=4%2F7
P(R then B)=%281%2F8%29%284%2F7%29=1%2F14