Question 306681: Only 1% of all American households do not have a color television set. A television marketing analyst randomly selects 160 American households.
How many households would he expect to not have a television set?What is the probability that 8 or more households do not have a television set?What is the probability than between 2 and 6 households (inclusive) do not have a color television set?
thank you!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Only 1% of all American households do not have a color television set. A television marketing analyst randomly selects 160 American households.
How many households would he expect to not have a television set?
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E(x) = np = 160*0.01 = 1.6
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What is the probability that 8 or more households do not have a television set?
Binomial problem with n = 160; p = 0.01
P(8 <= x <= 160) = 1 - P(0<= x <= 7) = 0.000232..
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What is the probability than between 2 and 6 households (inclusive) do not have a color television set?
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P(2<= x <= 6) = binomcdf(160,0.01,6)-binomcdf(160,0.01,1) = 0.4748
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Cheers,
Stan H.
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