SOLUTION: 1.69oz. bag of plain M&M's Total in bag: 57 Red: 6 -11% Yellow: 7 - 12% Orange: 8 - 14% Green: 13 - 23% Blue: 16 - 28% Brown: 7 - 12% I reach into the bag and pull out a

Algebra ->  Probability-and-statistics -> SOLUTION: 1.69oz. bag of plain M&M's Total in bag: 57 Red: 6 -11% Yellow: 7 - 12% Orange: 8 - 14% Green: 13 - 23% Blue: 16 - 28% Brown: 7 - 12% I reach into the bag and pull out a       Log On


   

Question 306532: 1.69oz. bag of plain M&M's
Total in bag: 57
Red: 6 -11%
Yellow: 7 - 12%
Orange: 8 - 14%
Green: 13 - 23%
Blue: 16 - 28%
Brown: 7 - 12%
I reach into the bag and pull out a green M&M. What is the probability that I will choose a green M&M again?

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Having removed one grren M&M you have 12 green ones left out of a total of 56.
12/56=.214 or 21.4 % chance of getting a second green M&M.