SOLUTION: whAt two numbers have a sum of 108 and a product of 2835

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Question 306394: whAt two numbers have a sum of 108 and a product of 2835
Answer by richwmiller(17219) About Me  (Show Source):
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a+b=108
a*b=2835
a=108-b
(108-b)*b=2835
108b-b^2=2835
b^2-108b+2835=0
prime factors of 2835=3*3*3*3*5*7
3*945
9*315
27*105
63*45
21*135
63*45
(b-63)*(b-45)=0