SOLUTION: 4x+2y=8.50,,,, 2x+3y = 5.75 what are values of x and y and how do you do it please show work so I can figure others out thx
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-> SOLUTION: 4x+2y=8.50,,,, 2x+3y = 5.75 what are values of x and y and how do you do it please show work so I can figure others out thx
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Question 306043: 4x+2y=8.50,,,, 2x+3y = 5.75 what are values of x and y and how do you do it please show work so I can figure others out thx Found 2 solutions by richwmiller, JBarnum:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! No idea what all those commas are.
What is "do it"?
Try to use math talk.
Dear Mr Barnum . I read fine. I was trying to teach the student to present his problem correctly. I am not having a bad night. Come down off of your high horse.
Apparently you so eager to show off you can't see that.
Yes, it was an easy problem. I am trying to teach on the forum not just spout answers.
You can put this solution on YOUR website! wow guess the tutor is having a bad night, this isnt a hard problem to do...apparently some tutors have a hard time reading.
there are 2 ways to solve one is elimination the other is substitution, u can do either to get the answer, i find elimination method faster.
multiply this line by 2
_______________ subtract the 2 lines
_______________
This is for any tutor that seems to have a problem with me answering student questions:
Sorry math and helping people give me a high so I cant really come down from it. Second if a tutor says they have no clue about something I dont see how that is called "teaching." If you dont know what it is dont answer the note and move to the next one. Maybe one should write something like: "I dont understand the problem as its written is there another way that you can write it so I can better help you with this problem?" but if you know the problem and then dont do it and dont write the solution completely then that tutor has not read the agreement they signed when becoming a tutor.