SOLUTION: Find equation, in standard form, of the line perpendicular to 3x - 6y =9 and passing through (-2, -1)

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Question 30575: Find equation, in standard form, of the line perpendicular to 3x - 6y =9 and passing through (-2, -1)
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+3x+-+6y+=9+ put in y=mx+b format
+-6y+=+-3x+%2B+9+ Divide by -6
+-6y%2F-6+=+-3x%2F-6+%2B+9%2F-6+
+y+=+1x%2F2+-+3%2F2+ since the slope (m) is +1/2 the slope of the line that is perpendicular to it is -2/1. Use this and the point to find the next line.
+y=mx%2Bb+
+-1=%28-2%29%28-2%29+%2B+b+ Solve for b
+-1+=+4+%2B+b+ subtract 4
+-5+=+b+ go back to y=mx+b with your slope and b values
+y+=+-2x+-+5+ put back into Ax+By=C (standard) format
+2x+%2B+y+=+-5+
Look at those nice right angles
+graph%28+300%2C+300%2C+-6%2C+6%2C+-6%2C+6%2C+%281x%2F2%29-%283%2F2%29%2C+-2x-5+%29+