SOLUTION: How do i go about solving questions such as 4x^2/3= 18 and 3^x=75 I am to solve for x.

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Question 305648: How do i go about solving questions such as 4x^2/3= 18 and 3^x=75
I am to solve for x.
Found 2 solutions by Alan3354, mananth:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do i go about solving questions such as
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4x^2/3= 18
x%5E%282%2F3%29+=+4.5
Cube both sides
x%5E2+=+4.5%5E3
x = ħ sqrt(4.5^3) = ħsqrt(91.125)
x =~ ħ 9.5459
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Take the log of both sides
3^x=75
xlog(3) = log(75)
x = log(75)/log(3)
x =~ 3.929947

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2/3= 18 and 3^x=75

4x^2 / 3 = 18
4x^2= 54
x^2= 54/4
X^2 = 13.5
+ / - x= sqrt 18