SOLUTION: What would the standard graphing form of these following equations be? I don't know if my answers are right to these.
x^2-4y^2-2x-8y=7
(y-2)^2-4(x+2)^2=4
(y+1)^2=-4(x-2)
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-> SOLUTION: What would the standard graphing form of these following equations be? I don't know if my answers are right to these.
x^2-4y^2-2x-8y=7
(y-2)^2-4(x+2)^2=4
(y+1)^2=-4(x-2)
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Question 305474: What would the standard graphing form of these following equations be? I don't know if my answers are right to these.
x^2-4y^2-2x-8y=7
(y-2)^2-4(x+2)^2=4
(y+1)^2=-4(x-2)
x^2-4x=y+4
x=2y^2-4y+5
x^2+y^2-6x+2y+9=0
(x+5)^2+4(y-4)^2=16
9x^2+4y^2-18x+16y-11=0
(y-2)^2-4(x+2)^2=4
x^2-4y^2-2x-8y=7
x^2-8x+13=y
9x^2+16y^2-64y-80=0
5x^2+5y^2=45
5x^2-6y^2-30x-12y=-9 Answer by Fombitz(32388) (Show Source):
