SOLUTION: when a question asks you to show something algebraically, DO NOT substitute numbers for the variables and give me an example. On the other hand, when a question asks you to show s

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Question 30537: when a question asks you to show something algebraically, DO NOT substitute numbers for the variables and give me an example. On the other hand, when a question asks you to show something numerically or to provide an example, you may substitute numbers for the variables. Show all work
Let A and B be two 2x2 matrices. Show by example that the determinant function is multiplicative, that is,
det(A)det(B) = det(AB)
(here you can pick numeric examples for A and B).
Bonus: show algebraically that the determinant function is multiplicative in the 2x2 case.

Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
I'll solve here the general case. We have two matrices:
A=%28matrix%282%2C2%2Ca1%2Ca2%2Ca3%2Ca4%29%29, B=%28matrix%282%2C2%2Cb1%2Cb2%2Cb3%2Cb4%29%29
Then we have that:
det%28A%29=a1a4-a3a2 and det%28B%29=b1b4-b3b2
Now consider the multiplication A*B. The result of the multiplication is:
A%2AB=%28matrix%282%2C2%2Ca1b1+%2B+a2b3%2C+a1b2+%2B+a2b4%2C+a3b1%2Ba4b3%2Ca3b2%2Ba4b4%29%29
Now let's find the determinant of this matrix:

After applying the distributive property to each multiplication, we get:
a1b1a3b2+%2B+a1b1a4b4+%2B+a2b3a3b2+%2B+a2b3a4b4+-+a3b1a1b2+-+a3b1a2b4+-+a4b3a1b2+-+a4b3a2b4
But some of these terms cancel each other out. Specifically, we have a1b1a3b2+-+a3b1a1b2+=+0 and a2b3a4b4+-+a4b3a2b4+=+0
We're left with
det%28A%2AB%29=a1b1a4b4+%2B+a2b3a3b2+-+a3b1a2b4+-+a4b3a1b2
Now, let's check that this is the same as det(A)*det(B):
det%28A%29%2Adet%28B%29+=+%28a1a4-a3a2%29%28b1b4-b3b2%29
Applying distributive property:
det%28A%29%2Adet%28B%29+=+a1a4b1b4+-+a1a4b3b2+-+a3a2b1b4+%2B+a3a2b3b2
Now compare the expressions we found for det(A*B) and for det(A)*det(B). Rearranging some of the factors in each term, they are exactly the same.
I hope this helps!
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