SOLUTION: For a two digit numbers its digit in the ten’s place is twice the digit in the unit’s place. When 8 is subtracted from the number digits at both places are equal. Find the number?
Algebra ->
Equations
-> SOLUTION: For a two digit numbers its digit in the ten’s place is twice the digit in the unit’s place. When 8 is subtracted from the number digits at both places are equal. Find the number?
Log On
Question 305366: For a two digit numbers its digit in the ten’s place is twice the digit in the unit’s place. When 8 is subtracted from the number digits at both places are equal. Find the number? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let x = the 10's digit
Let y = the units digit
Let z = the digits after 8 has been subtracted
10x + y = "the number"
:
Write an equation for each statement:
:
For a two digit numbers it's digit in the ten’s place is twice the digit in the unit’s place.
x = 2y
:
When 8 is subtracted from the number; digits at both places are equal.
10x + y - 8 = 10z + z
Replace x with 2y
10(2y) + y = 11z + 8
20y + y = 11z + 8
21y = 11z + 8
y = z +
The only value for z that gives an integer value for y, is 5
y = (5) +
y = z +
y = z
y = 3
then
x = 2(3)
x = 6
:
The number = 63
:
Check: 63 - 8 = 55
