SOLUTION: how many different positive three-digit integers can be formed if the three digits 4, 5, and 6 must be used in each of the integers?
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Question 305362: how many different positive three-digit integers can be formed if the three digits 4, 5, and 6 must be used in each of the integers? Found 2 solutions by Edwin McCravy, fasthomework:Answer by Edwin McCravy(20055) (Show Source):
Choose the first digit any of those three ways.
Choose the second digit in any of the remaining 2 ways.
Choose the third digit as the remaining 1 way.
That's 3*2*1 or 6 ways.
The 6 such three-digit integers are:
456, 465, 546, 564, 645, and 654
Edwin
You can put this solution on YOUR website! 4 5 6
4 6 5
5 4 6
5 6 4
6 4 5
6 5 4
3! or 6
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