SOLUTION: A 30-gallon solution is 80% salt. How much pure water must be added to produce a solution that is 60% salt?

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Question 304836: A 30-gallon solution is 80% salt. How much pure water must be added to produce a solution that is 60% salt?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let w = gallons of water to be added
.8%2A30+=+24 gallons of salt in 80% solution
24%2F%2830+%2B+w%29+=+.6
24+=+.6%2A%2830+%2B+w%29
24+=+18+%2B+.6w
.6w+=+24+-+18
.6w+=+6
w+=+10
10 gallons of water must be added