SOLUTION: A 30-gallon solution is 80% salt. How much pure water must be added to produce a solution that is 60% salt?

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Question 304835: A 30-gallon solution is 80% salt. How much pure water must be added to produce a solution that is 60% salt?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A 30-gallon solution is 80% salt.
How much pure water must be added to produce a solution that is 60% salt?
:
Let x = amt of water required
:
.8(30) = .6(x+30)
24 = .6x + 18
24 - 18 = .6x
6 = .6x
x = 6%2F.6
x = 10 gallons of water required
:
:
Check
.8(30) = .6(40)