SOLUTION: The largest of five consecutive integers is twice the smallest. Find the smallest integer. Ans. 4

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Question 304827: The largest of five consecutive integers is twice the smallest. Find the smallest integer.
Ans. 4
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE SMALLEST INTEGER & X+4 BE THE FIFTH CONSECUTIVE INTEGER.
X+4=2X
X-2X=-4
-X=-4
X=4 ANS.
PROOF
4+4=2*4
8=8