SOLUTION: Explain how to arrive at the vertex algebraically of the following function 6x^2 + 13x -8 please
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Question 304667
:
Explain how to arrive at the vertex algebraically of the following function
6x^2 + 13x -8
please
Answer by
richwmiller(17219)
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There is no y so there is no vertex
set it equal to y
-13/6*2=-13/12=x
plug that in for x and get the y of the vertex