SOLUTION: the sum of three numbers id 138. the second is 5 more than the smallest and the third is 10 more than the smallest. find the numbers.

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Question 304503: the sum of three numbers id 138. the second is 5 more than the smallest and the third is 10 more than the smallest. find the numbers.

Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
x+y+z=138
y=x+5
z=x+10
x+(x+5)+(x+10)=138
3x+15=138
3x=138-15
3x=123
x=123/3
x=41 ans.
y=41+5=46 ans.
z=41+10=51 ans.
Proof:
41+46+51=138
138=138

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Three numbers: x, y, z, (z is the largest)
:
the sum of three numbers is 138.
x + y + z = 138
:
the second is 5 more than the smallest
y = x + 5
:
and the third is 10 more than the smallest.
z = x + 10
:
find the numbers.
x + y + z = 138
Substitute
x + (x+5) + (x+10) = 138
:
3x + 15 = 138
3x = 138 - 15
3x = 123
x =
x = 41
then
y = 46
and
z = 51
;
:
Check: 41 + 46 + 51 = 138