SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40mph and train B is traveling at 48 mph. Train A passes a station at 7:20am. If Tra
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Question 304487: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40mph and train B is traveling at 48 mph. Train A passes a station at 7:20am. If Train B passes the same station at 7:35am, at what time will train B catch up with train A? Found 2 solutions by ankor@dixie-net.com, richwmiller:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 40mph and train B is traveling at 48 mph.
Train A passes a station at 7:20am.
If Train B passes the same station at 7:35am, at what time will train B catch up with train A?
:
from the given information, we know that train B is 15 min (1/4 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: * 48 = 12 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 12 mi
48t = 40t + 12
48t - 40t = 12
8t = 12
t =
t = 1.5 hr or 1 hr 30 min
:
7:20 + 1:30 = 8:50 am, B catches A
You can put this solution on YOUR website! A has a 15 minute head start. How far can a go in15 minutes?
40*1/4=10miles
train b is gaining on a at 8 mph
so it will take b r*t=d
t=d/r
t=10/8 to catch up
1 1/4 hour
add 1:15 to 7:35
8:50 train b acatches train a
