SOLUTION: Convert sqrt(3)x-y+3= 0 to a normal form of a line.
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Question 304415
:
Convert sqrt(3)x-y+3= 0 to a normal form of a line.
Answer by
stanbon(75887)
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Convert sqrt(3)x-y+3= 0 to a normal form of a line.
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y = sqrt(3)x + 3
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Cheers,
Stan H.