SOLUTION: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
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-> SOLUTION: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
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Question 304041: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius) Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
.
Complete the square:
From here we see that:
. square units
