SOLUTION: i need to find the altitude of the isoceles triangle. They gave me theda=52 degrees and b=4 inches
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Question 303800
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i need to find the altitude of the isoceles triangle. They gave me theda=52 degrees and b=4 inches
Answer by
Alan3354(69443)
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If b is the base and forms and is part of the 52 deg angle, then h = b*sin(52)
Area = bh/2 = b*b*sin(52)/2
= 8*sin(52)
=~ 6.304 sq inches
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PS It's theta