SOLUTION: how do i solve: x-3 over 5(x+4) times 4(x+4) over x-3

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Question 303308: how do i solve: x-3 over 5(x+4) times 4(x+4) over x-3
Found 2 solutions by jim_thompson5910, london maths tutor:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28%28x-3%29%2F%285%28x%2B4%29%29%29%28%284%28x%2B4%29%29%2F%28x-3%29%29 Start with the given expression.


%284%28x-3%29%28x%2B4%29%29%2F%285%28x%2B4%29%28x-3%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


4%2F5 Simplify


So %28%28x-3%29%2F%285%28x%2B4%29%29%29%28%284%28x%2B4%29%29%2F%28x-3%29%29 simplifies to 4%2F5


In other words, %28%28x-3%29%2F%285%28x%2B4%29%29%29%28%284%28x%2B4%29%29%2F%28x-3%29%29=4%2F5 where x%3C%3E-4 or x%3C%3E3

Answer by london maths tutor(243) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-3%29%2F%285%28x%2B4%29%29%2A%284%28x%2B4%29%29%2F%28x-3%29
cancel out (x-3) and (x+4)
=4/5