SOLUTION: n-2= square roots of 68-4n

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Question 303274: n-2= square roots of 68-4n
Answer by london maths tutor(243) About Me  (Show Source):
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n-2= square roots of 68-4n
n-2=sqrt%2868-4n%29
Taking square on both side of the equation:
%28n-2%29%5E2=%2868-4n%29
n%5E2-4n%2B4=68-4n
n%5E2-4n%2B4n%2B4-68=0
n%5E2-64=0
n%5E2=64
n=+%2B-+sqrt%2864%29
n =+-8